260A - Adding Digits - CodeForces Solution


implementation math *1400

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Python Code:

a,b,n=map(int, input().split())
num = a
flag=0
ans=str(a)
for i in range(n):
    if num%b==0:
        ans+="0"
    else:
        ost = (num*10)%b
        if ost==0:
            ans+=str(0)
        elif (b-ost)>9:
            print(-1)
            flag=1
            break
        
        else:
                        ans+=str(b-ost)
    num = 0
if flag==0:
    print(ans)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define gcd __gcd


int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    ll n , k , num;
    string str = "";
    cin >> n >> k >> num;
    vector<int> vec;
    while(num)
    {
        for(int i = 0 ; i < 10 ; ++i)
        {
            int temp = n * 10 + i;
            if(!(temp % k))
            {
                auto f = find(vec.begin() , vec.end() , i);
                if(f != vec.end())
                {
                    str = to_string(n);
                    int x = f - vec.begin();
                    while(num)
                    {
                        for(int j = x ; j < vec.size() ; ++j , --num)
                        {
                            str += to_string(vec[j]);
                            if(!num)
                                break;
                        }
                    }
                    cout << str;
                    return 0;
                }
                n = temp;
                vec.emplace_back(i);
                break;
            }
            if(i == 9)
            {
                cout << -1;
                return 0;
            }
        }
        --num;
    }
    cout << n;
    return 0;
}



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